Optimal. Leaf size=52 \[ \frac{a^2 \log (\sinh (c+d x))}{d}-\frac{(a+b)^2 \text{csch}^4(c+d x)}{4 d}-\frac{a (a+b) \text{csch}^2(c+d x)}{d} \]
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Rubi [A] time = 0.0939137, antiderivative size = 52, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.13, Rules used = {4138, 444, 43} \[ \frac{a^2 \log (\sinh (c+d x))}{d}-\frac{(a+b)^2 \text{csch}^4(c+d x)}{4 d}-\frac{a (a+b) \text{csch}^2(c+d x)}{d} \]
Antiderivative was successfully verified.
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Rule 4138
Rule 444
Rule 43
Rubi steps
\begin{align*} \int \coth ^5(c+d x) \left (a+b \text{sech}^2(c+d x)\right )^2 \, dx &=-\frac{\operatorname{Subst}\left (\int \frac{x \left (b+a x^2\right )^2}{\left (1-x^2\right )^3} \, dx,x,\cosh (c+d x)\right )}{d}\\ &=-\frac{\operatorname{Subst}\left (\int \frac{(b+a x)^2}{(1-x)^3} \, dx,x,\cosh ^2(c+d x)\right )}{2 d}\\ &=-\frac{\operatorname{Subst}\left (\int \left (-\frac{(a+b)^2}{(-1+x)^3}-\frac{2 a (a+b)}{(-1+x)^2}-\frac{a^2}{-1+x}\right ) \, dx,x,\cosh ^2(c+d x)\right )}{2 d}\\ &=-\frac{a (a+b) \text{csch}^2(c+d x)}{d}-\frac{(a+b)^2 \text{csch}^4(c+d x)}{4 d}+\frac{a^2 \log (\sinh (c+d x))}{d}\\ \end{align*}
Mathematica [A] time = 0.232371, size = 77, normalized size = 1.48 \[ -\frac{\left (a \cosh ^2(c+d x)+b\right )^2 \left (-4 a^2 \log (\sinh (c+d x))+(a+b)^2 \text{csch}^4(c+d x)+4 a (a+b) \text{csch}^2(c+d x)\right )}{d (a \cosh (2 (c+d x))+a+2 b)^2} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.046, size = 142, normalized size = 2.7 \begin{align*}{\frac{{a}^{2}\ln \left ( \sinh \left ( dx+c \right ) \right ) }{d}}-{\frac{{a}^{2} \left ({\rm coth} \left (dx+c\right ) \right ) ^{2}}{2\,d}}-{\frac{{a}^{2} \left ({\rm coth} \left (dx+c\right ) \right ) ^{4}}{4\,d}}-{\frac{ab \left ( \cosh \left ( dx+c \right ) \right ) ^{2}}{2\,d \left ( \sinh \left ( dx+c \right ) \right ) ^{4}}}-{\frac{ab \left ( \cosh \left ( dx+c \right ) \right ) ^{2}}{2\,d \left ( \sinh \left ( dx+c \right ) \right ) ^{2}}}-{\frac{{b}^{2} \left ( \cosh \left ( dx+c \right ) \right ) ^{2}}{4\,d \left ( \sinh \left ( dx+c \right ) \right ) ^{4}}}+{\frac{{b}^{2} \left ( \cosh \left ( dx+c \right ) \right ) ^{2}}{4\,d \left ( \sinh \left ( dx+c \right ) \right ) ^{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.15157, size = 381, normalized size = 7.33 \begin{align*} a^{2}{\left (x + \frac{c}{d} + \frac{\log \left (e^{\left (-d x - c\right )} + 1\right )}{d} + \frac{\log \left (e^{\left (-d x - c\right )} - 1\right )}{d} + \frac{4 \,{\left (e^{\left (-2 \, d x - 2 \, c\right )} - e^{\left (-4 \, d x - 4 \, c\right )} + e^{\left (-6 \, d x - 6 \, c\right )}\right )}}{d{\left (4 \, e^{\left (-2 \, d x - 2 \, c\right )} - 6 \, e^{\left (-4 \, d x - 4 \, c\right )} + 4 \, e^{\left (-6 \, d x - 6 \, c\right )} - e^{\left (-8 \, d x - 8 \, c\right )} - 1\right )}}\right )} + 4 \, a b{\left (\frac{e^{\left (-2 \, d x - 2 \, c\right )}}{d{\left (4 \, e^{\left (-2 \, d x - 2 \, c\right )} - 6 \, e^{\left (-4 \, d x - 4 \, c\right )} + 4 \, e^{\left (-6 \, d x - 6 \, c\right )} - e^{\left (-8 \, d x - 8 \, c\right )} - 1\right )}} + \frac{e^{\left (-6 \, d x - 6 \, c\right )}}{d{\left (4 \, e^{\left (-2 \, d x - 2 \, c\right )} - 6 \, e^{\left (-4 \, d x - 4 \, c\right )} + 4 \, e^{\left (-6 \, d x - 6 \, c\right )} - e^{\left (-8 \, d x - 8 \, c\right )} - 1\right )}}\right )} - \frac{4 \, b^{2}}{d{\left (e^{\left (d x + c\right )} - e^{\left (-d x - c\right )}\right )}^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 2.23174, size = 3093, normalized size = 59.48 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.43632, size = 198, normalized size = 3.81 \begin{align*} -\frac{12 \, a^{2} d x - 12 \, a^{2} \log \left ({\left | e^{\left (2 \, d x + 2 \, c\right )} - 1 \right |}\right ) + \frac{25 \, a^{2} e^{\left (8 \, d x + 8 \, c\right )} - 52 \, a^{2} e^{\left (6 \, d x + 6 \, c\right )} + 48 \, a b e^{\left (6 \, d x + 6 \, c\right )} + 102 \, a^{2} e^{\left (4 \, d x + 4 \, c\right )} + 48 \, b^{2} e^{\left (4 \, d x + 4 \, c\right )} - 52 \, a^{2} e^{\left (2 \, d x + 2 \, c\right )} + 48 \, a b e^{\left (2 \, d x + 2 \, c\right )} + 25 \, a^{2}}{{\left (e^{\left (2 \, d x + 2 \, c\right )} - 1\right )}^{4}}}{12 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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